加密解密 10 months ago red.ghostwolflab.com 3 minutes 在线网站 网址 解释 https://gchq.github.io/CyberChef/ CyberChef(网络厨师) https://www.dcode.fr/ 加密解密、数学、代码、在线计算 https://crackstation.net/ 免费密码HASH破解器 https://www.base64encode.org/ Base64编码 https://www.base64decode.org/ Base64解码 https://rumkin.com/tools/cipher/ Rumkin密码和代码解密工具 https://www.unphp.net 在线PHP代码解密 https://cmd5.com/ MD5在线解密破解 https://www.somd5.com/ MD5免费在线解密破解 https://www.boxentriq.com/ 密码破译和逻辑谜题解决工具 https://quipqiup.com/ 自动化密码破解 https://www.nayuki.io/page/automatic-caesar-cipher-breaker-javascript 自动凯撒密码破解 Fernet解密 https://asecuritysite.com/encryption/ferdecode from cryptography.fernet import Fernet key = "" token = "" cipher = Fernet(key) decoded = cipher.decrypt(token) Malbloge解密 http://www.malbolge.doleczek.pl/ https://zb3.me/malbolge-tools/ Dvorak Keyboard解密 https://www.geocachingtoolbox.com/index.php?lang=en&page=dvorakKeyboard DTFM解密 http://dl.djsoft.net/DTMFChecker.zip https://www.dcode.fr/prime-numbers-cipher Bcrypt解密 git clone https://github.com/BREAKTEAM/Debcrypt python3 crack.py Cistercian Monk解密 https://www.dcode.fr/cistercian-numbers Vigenere解密 https://www.dcode.fr/vigenere-cipher 多次点击电话代码转换 https://www.dcode.fr/code-multitap-abc http://rumkin.com/tools/cipher/atbash.php 异或消息解密 git clone https://github.com/laconicwolf/crypto-tools python3 crack_repeating_key_xor.py -f <file> -x RSA PKCS#1解密 from Crypto.PublicKey import RSA from Crypto.Cipher import PKCS1_v1_5 import cryptastib as ca ca.queries = 0 # key = RSA.generate(1024, e=3) # print repr((key.n, key.e, key.d)) (N, e, d) = (151242689083100816738181002620937999512181809379387195583593491291603542900108691523222285405372857139696327669320405999262960106462050217947074001784527818795198802600940780900545580866814212880284349556332186821342122597851846151778484011876082986461493379210023160659498744772656523909821057886586431311599L, 3L, 100828459388733877825454001747291999674787872919591463722395660861069028600072461015481523603581904759797551779546937332841973404308033478631382667856351862771810527368138135852999223344751183054387918163104751737882143190101541038691020249177008890480468119734661689468498909557170851608519691070322297440427L) key = RSA.construct((N, e, d)) plaintext = '\x02BJ\xe2s^\x1a\x9f\xcfAS\xceGZ\xa0\x99n\xae\x1d;\xd6N\xbb\xf6\xcd\xaf\xb5\'$\x81/0w\xf8\x88"\xb6\xda\xbb\x86\xb6\x9b\xb4z\xde\x04\xd4\xbd\xcf\x17\xe5\xe3G#\x1fv\xabP\x17$015\xb5/il\x12U\xdf0\x1b\xdcEl\x0fQw`\x02#\xd4kQ\x1a/\x89\xfa\x15\x04U\xef>\x90v\xee\x01O\xde\x9d\x0bi\x17\xd1\x16\xe2\x8b\xfa\x087\xb3\x83\x00test plaintext' ciphertext = key.encrypt(plaintext, 0)[0] def oracle(ciphertext): plaintext = key.decrypt(ciphertext) ca.queries += 1 return plaintext.encode('hex')[:2] == '02' print 'Testing Bleichenbacher\'s oracle...' decrypted = ca.bb98_padding_oracle(ciphertext, oracle, key.e, key.n, verbose=True, debug=False) print "Plaintext is %r" % key.decrypt(ciphertext) print "Attack produced plaintext of %r" % (decrypted) if decrypted != key.decrypt(ciphertext): print "Failed with %d queries" % ca.queries raise BleichenbacherAttackFailedError else: print "Succeeded with %d queries" % ca.queries 无需私钥,使用公钥解密enc文件 git clone https://github.com/RsaCtfTool/RsaCtfTool python3 RsaCtfTool.py --publickey ./key.pub --private openssl rsautl -decrypt -inkey key.pri -in flag.enc -out flag.txt 终端中解密Base64 echo 'R2hvc3RfV29sZl9MYWI=' | base64 -d Github 下载工具Cipheyhttps://github.com/Ciphey/Ciphey